如何选择适合的高效固定定位架构

// 学生信息数据库
std::unordered_map<std::string, StudentInfo> studentDatabase;

// 添加学生信息
StudentInfo student;
student.name = "张三";
student.number = "2001001";
student.age = 20;
studentDatabase.insert(std::make_pair(student.number, student));

// 查找学生信息
std::string number = "2001001";
auto iter = studentDatabase.find(number);
if (iter != studentDatabase.end()) {
    StudentInfo student = iter->second;
    std::cout << "姓名：" << student.name << std::endl;
    std::cout << "学号：" << student.number << std::endl;
    std::cout << "年龄：" << student.age << std::endl;
}

// 员工信息结构体
struct EmployeeInfo {
    std::string name;
    std::string department;
    int salary;
};

// 员工信息比较函数
bool compareBySalary(const EmployeeInfo& employee1, const EmployeeInfo& employee2) {
    return employee1.salary < employee2.salary;
}

// 员工信息数据库
std::set<EmployeeInfo, decltype(compareBySalary)*> employeeDatabase(compareBySalary);

// 添加员工信息
EmployeeInfo employee1;
employee1.name = "张三";
employee1.department = "销售部";
employee1.salary = 3000;
employeeDatabase.insert(employee1);

EmployeeInfo employee2;
employee2.name = "李四";
employee2.department = "技术部";
employee2.salary = 5000;
employeeDatabase.insert(employee2);

// 查找工资在[4000, 6000]范围内的员工信息
EmployeeInfo employee;
employee.salary = 4000;
auto iter = employeeDatabase.lower_bound(employee);

while (iter != employeeDatabase.end() && iter->salary <= 6000) {
    std::cout << "姓名：" << iter->name << std::endl;
    std::cout << "部门：" << iter->department << std::endl;
    std::cout << "工资：" << iter->salary << std::endl;
    ++iter;
}