如何使用PHP实现微信小程序的任务反馈功能？

CREATE TABLE `task_feedback` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `task_id` int(11) NOT NULL,
  `user_id` int(11) NOT NULL,
  `content` text NOT NULL,
  `created_at` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8mb4;

<?php
// 解析JSON数据
$postData = json_decode(file_get_contents('php://input'), true);

// 连接数据库
$servername = "localhost";
$username = "your_username";
$passWord = "your_password";
$dbname = "your_database";

$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
    die("连接数据库失败: " . $conn->connect_error);
}

// 插入反馈数据
$stmt = $conn->prepare("INSERT INTO task_feedback (task_id, user_id, content) VALUES (?, ?, ?)");
$stmt->bind_param("iis", $taskId, $userId, $content);

$taskId = $postData['taskId'];
$userId = $postData['userId'];
$content = $postData['content'];

if ($stmt->execute()) {
    $response = array('success' => true, 'message' => '反馈成功');
} else {
    $response = array('success' => false, 'message' => '反馈失败');
}

// 返回JSON响应
header('Content-Type: application/json');
echo json_encode($response);

$stmt->close();
$conn->close();
?>

wx.request({
  url: 'https://your_domain/feedback.php',
  method: 'POST',
  data: {
    taskId: 1,
    userId: 123,
    content: '这是一个任务反馈'
  },
  success: function(res) {
    console.log(res.data);
  },
  fail: function(res) {
    console.log('请求失败');
  }
})