一、插入数据INSERT1.插入完整数据(顺序插入)语法一:INSERT INTO 表名(字段1, 字段2, 字段3…字段n) VALUES(值1, 值2, 值3…值n);语法二:INSERT INTO 表
一、插入数据INSERT
#针对所有库的授权:*.*
grant select on *.* to 'li'@'localhost' identified by '123'; #只在user表中可以查到li用户的select权限被设置为Y
#针对某一数据库:db1.*
grant select on db1.* to 'wang'@'%' identified by '123'; #只在db表中可以查到wang用户的select权限被设置为Y
#针对某一个表:db1.t1
grant select on db1.t1 to 'tom'@'%' identified by '123'; #只在tables_priv表中可以查到tom用户的select权限
#针对某一个字段:
mysql> select * from t3;
+------+-------+------+
| id | name | age |
+------+-------+------+
| 1 | egon1 | 18 |
| 2 | egon2 | 19 |
| 3 | egon3 | 29 |
+------+-------+------+
grant select (id,name),update (age) on db1.t3 to 'egon4'@'localhost' identified by '123';
#可以在tables_priv和columns_priv中看到相应的权限
mysql> select * from tables_priv where user='egon4'\G
mysql> select * from columns_priv where user='egon4'\G
#删除权限
revoke select on db1.* to 'alex'@'%';
#创建表
create database company;
use company;
create table employee(
id int not null unique auto_increment,
name varchar(20) not null,
sex enum('male','female') not null default 'male',
age int(3) unsigned not null default 28,
hire_date date not null,
post varchar(50),
post_comment varchar(100),
salary double(15,2),
office int,
depart_id int
);
#插入记录三个部门:教学,销售,运营
insert into employee(name,sex,age,hire_date,post,salary,office,depart_id) values
('wang','male',18,'20170301','teacher',7300.33,401,1),
('li','male',78,'20150302','teacher',1000000.31,401,1),
('jim','male',81,'20130305','teacher',8300,401,1),
('zhao','male',73,'20140701','teacher',3500,401,1),
('liwenzhou','male',28,'20121101','teacher',2100,401,1),
('jingliyang','female',18,'20110211','teacher',9000,401,1),
('jinxin','male',18,'19000301','teacher',30000,401,1),
('成龙','male',48,'20101111','teacher',10000,401,1),
('歪歪','female',48,'20150311','sale',3000.13,402,2),
('丫丫','female',38,'20101101','sale',2000.35,402,2),
('丁丁','female',18,'20110312','sale',1000.37,402,2),
('星星','female',18,'20160513','sale',3000.29,402,2),
('格格','female',28,'20170127','sale',4000.33,402,2),
('张野','male',28,'20160311','operation',10000.13,403,3),
('程咬金','male',18,'19970312','operation',20000,403,3),
('程咬银','female',18,'20130311','operation',19000,403,3),
('程咬铜','male',18,'20150411','operation',18000,403,3),
('程咬铁','female',18,'20140512','operation',17000,403,3)
;
+----+------------+--------+-----+------------+-----------+--------------+------------+--------+-----------+
| id | name | sex | age | hire_date | post | post_comment | salary | office | depart_id |
+----+------------+--------+-----+------------+-----------+--------------+------------+--------+-----------+
| 1 | wang | male | 18 | 2017-03-01 | teacher | NULL | 7300.33 | 401 | 1 |
| 2 | li | male | 78 | 2015-03-02 | teacher | NULL | 1000000.31 | 401 | 1 |
| 3 | jim | male | 81 | 2013-03-05 | teacher | NULL | 8300.00 | 401 | 1 |
| 4 | zhao | male | 73 | 2014-07-01 | teacher | NULL | 3500.00 | 401 | 1 |
| 5 | liwenzhou | male | 28 | 2012-11-01 | teacher | NULL | 2100.00 | 401 | 1 |
| 6 | jingliyang | female | 18 | 2011-02-11 | teacher | NULL | 9000.00 | 401 | 1 |
| 7 | jinxin | male | 18 | 1900-03-01 | teacher | NULL | 30000.00 | 401 | 1 |
| 8 | 成龙 | male | 48 | 2010-11-11 | teacher | NULL | 10000.00 | 401 | 1 |
| 9 | 歪歪 | female | 48 | 2015-03-11 | sale | NULL | 3000.13 | 402 | 2 |
| 10 | 丫丫 | female | 38 | 2010-11-01 | sale | NULL | 2000.35 | 402 | 2 |
| 11 | 丁丁 | female | 18 | 2011-03-12 | sale | NULL | 1000.37 | 402 | 2 |
| 12 | 星星 | female | 18 | 2016-05-13 | sale | NULL | 3000.29 | 402 | 2 |
| 13 | 格格 | female | 28 | 2017-01-27 | sale | NULL | 4000.33 | 402 | 2 |
| 14 | 张野 | male | 28 | 2016-03-11 | operation | NULL | 10000.13 | 403 | 3 |
| 15 | 程咬金 | male | 18 | 1997-03-12 | operation | NULL | 20000.00 | 403 | 3 |
| 16 | 程咬银 | female | 18 | 2013-03-11 | operation | NULL | 19000.00 | 403 | 3 |
| 17 | 程咬铜 | male | 18 | 2015-04-11 | operation | NULL | 18000.00 | 403 | 3 |
| 18 | 程咬铁 | female | 18 | 2014-05-12 | operation | NULL | 17000.00 | 403 | 3 |
+----+------------+--------+-----+------------+-----------+--------------+------------+--------+-----------+
# 简单查询
SELECT id, name, sex, age, hire_date, post, post_comment, salary, office, depart_id FROM employee;
SELECT * FROM employee;
SELECT name, salary FROM employee;
# 避免重复DISTINCT
SELECT DISTINCT post FROM employee;
+-----------+
| post |
+-----------+
| teacher |
| sale |
| operation |
+-----------+
# 通过四则运算查询
SELECT name, salary * 12 FROM employee;
SELECT name, salary * 12 AS Annual_salary FROM employee;
SELECT name, salary * 12 Annual_salary FROM employee;
+------------+---------------+
| name | Annual_salary |
+------------+---------------+
| wang | 87603.96 |
| li | 12000003.72 |
| jim | 99600.00 |
| zhao | 42000.00 |
| liwenzhou | 25200.00 |
| jingliyang | 108000.00 |
| jinxin | 360000.00 |
| 成龙 | 120000.00 |
| 歪歪 | 36001.56 |
| 丫丫 | 24004.20 |
| 丁丁 | 12004.44 |
| 星星 | 36003.48 |
| 格格 | 48003.96 |
| 张野 | 120001.56 |
| 程咬金 | 240000.00 |
| 程咬银 | 228000.00 |
| 程咬铜 | 216000.00 |
| 程咬铁 | 204000.00 |
+------------+---------------+
# 定义显示格式
CONCAT() 函数用于连接字符串
SELECT CONCAT('姓名: ', name, ' 年薪: ', salary * 12) AS Annual_salary FROM employee;
CONCAT_WS() 第一个参数为分隔符
SELECT CONCAT_WS(':', name, salary * 12) AS Annual_salary FROM employee;
+----------------------+
| Annual_salary |
+----------------------+
| wang:87603.96 |
| li:12000003.72 |
| jim:99600.00 |
| zhao:42000.00 |
| liwenzhou:25200.00 |
| jingliyang:108000.00 |
| jinxin:360000.00 |
| 成龙:120000.00 |
| 歪歪:36001.56 |
| 丫丫:24004.20 |
| 丁丁:12004.44 |
| 星星:36003.48 |
| 格格:48003.96 |
| 张野:120001.56 |
| 程咬金:240000.00 |
| 程咬银:228000.00 |
| 程咬铜:216000.00 |
| 程咬铁:204000.00 |
+----------------------+
练习:select concat('<名字:',name,'> ','<薪资:',salary,'>') from employee;
select distinct depart_id from employee;
select name,salary*12 annual_salary from employee;
# 1:单条件查询
SELECT name FROM employee WHERE post = 'sale';
# 2:多条件查询
SELECT name, salary FROM employee WHERE post = 'teacher' AND salary > 10000;
# 3:关键字BETWEEN AND
SELECT name, salary FROM employee WHERE salary BETWEEN 10000 AND 20000;
SELECT name, salary FROM employee WHERE salary NOT BETWEEN 10000 AND 20000;
# 4:关键字IS NULL(判断某个字段是否为NULL不能用等号,需要用IS)
SELECT name, post_comment FROM employee WHERE post_comment IS NULL;
SELECT name, post_comment FROM employee WHERE post_comment IS NOT NULL;
SELECT name, post_comment FROM employee WHERE post_comment = ''; #注意''是空字符串,不是null
ps:
执行
update employee set post_comment = '' where id = 2;
再用上条查看,就会有结果了
# 5:关键字IN集合查询
SELECT name, salary FROM employee WHERE salary = 3000 OR salary = 3500 OR salary = 4000 OR salary = 9000;
SELECT name, salary FROM employee WHERE salary IN(3000, 3500, 4000, 9000);
SELECT name, salary FROM employee WHERE salary NOT IN(3000, 3500, 4000, 9000);
# 6:关键字LIKE模糊查询
通配符’ % ’
SELECT * FROM employee WHERE name LIKE 'eg%';
通配符’_’
SELECT * FROM employee WHERE name LIKE 'al__';
select name,age from employee where post = 'teacher';
select name,age from employee where post='teacher' and age > 30;
select name,age,salary from employee where post='teacher' and salary between 9000 and 10000;
select * from employee where post_comment is not null;
select name,age,salary from employee where post='teacher' and salary in (10000,9000,30000);
select name,age,salary from employee where post='teacher' and salary not in (10000,9000,30000);
select name,salary*12 from employee where post='teacher' and name like 'jin%';
mysql> select name,salary*12 as year_salary from employee where post='teacher' and name like 'jin%';
mysql> select post,group_concat(name) from employee group by post;
mysql> select post,count(id) from employee group by post;
mysql> select sex,count(id) from employee group by sex;
mysql> select post,avg(salary) from employee group by post;
mysql> select post,max(salary) from employee group by post;
mysql> select post,min(salary) from employee group by post;
mysql> select sex,avg(salary) from employee group by sex;
mysql> select post,group_concat(name),count(id) from employee group by post having count(id) < 2;
mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000;
mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 and avg(salary) <20000;
mysql> select * from employee ORDER BY age asc,hire_date desc;
mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) asc;
mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) desc;
SELECT * FROM employee ORDER BY salary DESC LIMIT 3; # 默认初始位置为0
SELECT * FROM employee ORDER BY salary DESC LIMIT 0, 5; # 从第0开始,即先查询出第一条,然后包含这一条在内往后查5条
SELECT * FROM employee ORDER BY salary DESC LIMIT 5, 5; # 从第5开始,即先查询出第6条,然后包含这一条在内往后查5条
mysql> select * from employee limit 0,5; #显示第1到5条记录
mysql> select * from employee limit 5,5; #显示第5到10条记录
mysql> select * from employee limit 10,5; #显示第10到15条记录
SELECT * FROM employee WHERE name REGEXP '^ale';
SELECT * FROM employee WHERE name REGEXP 'on$';
SELECT * FROM employee WHERE name REGEXP 'm{2}';
create table department(id int,name varchar(20));
create table employee(
id int primary key auto_increment,
name varchar(20),
sex enum('male','female') not null default 'male',
age int,
dep_id int
);
#插入数据
insert into department values(200,'技术'),(201,'人力资源'),(202,'销售'),(203,'运营');
insert into employee(name,sex,age,dep_id) values
('egon','male',18,200),
('alex','female',48,201),
('wupeiqi','male',38,201),
('yuanhao','female',28,202),
('liwenzhou','male',18,200),
('jingliyang','female',18,204)
;
mysql> select * from department;
+------+--------------+
| id | name |
+------+--------------+
| 200 | 技术 |
| 201 | 人力资源 |
| 202 | 销售 |
| 203 | 运营 |
+------+--------------+
mysql> select * from employee;
+----+------------+--------+------+--------+
| id | name | sex | age | dep_id |
+----+------------+--------+------+--------+
| 1 | egon | male | 18 | 200 |
| 2 | alex | female | 48 | 201 |
| 3 | wupeiqi | male | 38 | 201 |
| 4 | yuanhao | female | 28 | 202 |
| 5 | liwenzhou | male | 18 | 200 |
| 6 | jingliyang | female | 18 | 204 |
+----+------------+--------+------+--------+
mysql> select * from employee,department;
mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee inner join department on employee.dep_id=department.id;
+----+-----------+------+--------+--------------+
| id | name | age | sex | name |
+----+-----------+------+--------+--------------+
| 1 | egon | 18 | male | 技术 |
| 2 | alex | 48 | female | 人力资源 |
| 3 | wupeiqi | 38 | male | 人力资源 |
| 4 | yuanhao | 28 | female | 销售 |
| 5 | liwenzhou | 18 | male | 技术 |
+----+-----------+------+--------+--------------+
mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee,department where employee.dep_id=department.id;
mysql> select employee.id,employee.name,department.name as depart_name from employee left join department on employee.dep_id=department.id;
+----+------------+--------------+
| id | name | depart_name |
+----+------------+--------------+
| 1 | egon | 技术 |
| 5 | liwenzhou | 技术 |
| 2 | alex | 人力资源 |
| 3 | wupeiqi | 人力资源 |
| 4 | yuanhao | 销售 |
| 6 | jingliyang | NULL |
+----+------------+--------------+
mysql> select employee.id,employee.name,department.name as depart_name from employee right join department on employee.dep_id=department.id;
+------+-----------+--------------+
| id | name | depart_name |
+------+-----------+--------------+
| 1 | egon | 技术 |
| 2 | alex | 人力资源 |
| 3 | wupeiqi | 人力资源 |
| 4 | yuanhao | 销售 |
| 5 | liwenzhou | 技术 |
| NULL | NULL | 运营 |
+------+-----------+--------------+
select * from employee left join department on employee.dep_id = department.id
uNIOn
select * from employee right join department on employee.dep_id = department.id
;
+------+------------+--------+------+--------+------+--------------+
| id | name | sex | age | dep_id | id | name |
+------+------------+--------+------+--------+------+--------------+
| 1 | egon | male | 18 | 200 | 200 | 技术 |
| 5 | liwenzhou | male | 18 | 200 | 200 | 技术 |
| 2 | alex | female | 48 | 201 | 201 | 人力资源 |
| 3 | wupeiqi | male | 38 | 201 | 201 | 人力资源 |
| 4 | yuanhao | female | 28 | 202 | 202 | 销售 |
| 6 | jingliyang | female | 18 | 204 | NULL | NULL |
| NULL | NULL | NULL | NULL | NULL | 203 | 运营 |
+------+------------+--------+------+--------+------+--------------+
#注意 union与union all的区别:union会去掉相同的纪录
#示例1:以内连接的方式查询employee和department表,并且employee表中的age字段值必须大于25,即找出年龄大于25岁的员工以及员工所在的部门
select employee.name,department.name from employee inner join department on employee.dep_id = department.id where age > 25;
+---------+--------------+
| name | name |
+---------+--------------+
| alex | 人力资源 |
| wupeiqi | 人力资源 |
| yuanhao | 销售 |
+---------+--------------+
#示例2:以内连接的方式查询employee和department表,并且以age字段的升序方式显示
select employee.id,employee.name,employee.age,department.name from employee,department where employee.dep_id = department.id and age > 25 order by age asc;
+----+---------+------+--------------+
| id | name | age | name |
+----+---------+------+--------------+
| 4 | yuanhao | 28 | 销售 |
| 3 | wupeiqi | 38 | 人力资源 |
| 2 | alex | 48 | 人力资源 |
+----+---------+------+--------------+
#查询平均年龄在25岁以上的部门名
select id,name from department where id in (select dep_id from employee group by dep_id having avg(age) > 25);
#查看技术部员工姓名
select name from employee where dep_id in (select id from department where name='技术');
#查看不足1人的部门名(子查询得到的是有人的部门id)
select name from department where id not in (select distinct dep_id from employee);
#查询大于所有人平均年龄的员工名与年龄
mysql> select name,age from emp where age > (select avg(age) from emp);
#查询大于部门内平均年龄的员工名、年龄
select t1.name,t1.age from emp t1
inner join
(select dep_id,avg(age) avg_age from emp group by dep_id) t2 on t1.dep_id = t2.dep_id where t1.age > t2.avg_age;
#department表中存在dept_id=203,Ture
mysql> select * from employee where exists (select id from department where id=200);
#department表中存在dept_id=205,False
mysql> select * from employee where exists (select id from department where id=204);
--结束END--
本文标题: mysql数据操作
本文链接: https://lsjlt.com/news/40742.html(转载时请注明来源链接)
有问题或投稿请发送至: 邮箱/279061341@qq.com QQ/279061341
2024-10-23
2024-10-22
2024-10-22
2024-10-22
2024-10-22
2024-10-22
2024-10-22
2024-10-22
2024-10-22
2024-10-22
回答
回答
回答
回答
回答
回答
回答
回答
回答
回答
0