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替换pandas DataFram中的 NaN 值 问题 NaN 代表 Not A Number,是表示数据中缺失值的常用方法之一。它是一个特殊的浮点值,不能转换为 float 以外的任何其他类型。N
NaN 代表 Not A Number,是表示数据中缺失值的常用方法之一。它是一个特殊的浮点值,不能转换为 float 以外的任何其他类型。NaN 值是数据分析中的主要问题之一。为了得到理想的结果,对 NaN 进行处理是非常必要的。
用零替换Pandas DataFram中的 NaN 值的方法:
下面以替换为0举例, 可以替换为任意值,依照个人情况考虑。关于上述两个函数的用法,可以参考官方链接,功能很强大。
fillna()
:df['DataFrame Column'] = df['DataFrame Column'].fillna(0)
replace
:df['DataFrame Column'] = df['DataFrame Column'].replace(np.nan, 0)
fillna()
:df.fillna(0)
replace
:df.replace(np.nan, 0)
fillna()
# importing librariesimport pandas as pdimport numpy as np nums = {'Set_of_Numbers': [2, 3, 5, 7, 11, 13, np.nan, 19, 23, np.nan]} # Create the dataframedf = pd.DataFrame(nums, columns =['Set_of_Numbers']) # Apply the functiondf['Set_of_Numbers'] = df['Set_of_Numbers'].fillna(0) # print the DataFramedf
replace()
# importing librariesimport pandas as pdimport numpy as np nums = {'Car Model Number': [223, np.nan, 237, 195, np.nan, 575, 110, 313, np.nan, 190, 143, np.nan], 'Engine Number': [4511, np.nan, 7570, 1565, 1450, 3786, 2995, 5345, 7777, 2323, 2785, 1120]} # Create the dataframedf = pd.DataFrame(nums, columns=['Car Model Number']) # Apply the functiondf['Car Model Number'] = df['Car Model Number'].replace(np.nan, 0) # print the DataFramedf
fillna()
# importing librariesimport pandas as pdimport numpy as np nums = {'Number_set_1': [0, 1, 1, 2, 3, 5, np.nan, 13, 21, np.nan], 'Number_set_2': [3, 7, np.nan, 23, 31, 41, np.nan, 59, 67, np.nan], 'Number_set_3': [2, 3, 5, np.nan, 11, 13, 17, 19, 23, np.nan]} # Create the dataframedf = pd.DataFrame(nums) # Apply the functiondf = df.fillna(0) # print the DataFramedf
replace()
# importing librariesimport pandas as pdimport numpy as np nums = { 'Student Name': [ 'Shrek', 'Shivansh', 'Ishdeep', 'Siddharth', 'Nakul', 'Prakhar', 'Yash', 'Srikar', 'Kaustubh', 'Aditya', 'Manav', 'Dubey'], 'Roll No.': [ 18229, 18232, np.nan, 18247, 18136, np.nan, 18283, 18310, 18102, 18012, 18121, 18168], 'Subject ID': [204, np.nan, 201, 105, np.nan, 204, 101, 101, np.nan, 165, 715, np.nan], 'Grade Point': [9, np.nan, 7, np.nan, 8, 7, 9, 10, np.nan, 9, 6, 8]}# Create the dataframedf = pd.DataFrame(nums) # Apply the functiondf = df.replace(np.nan, 0) # print the DataFramedf
来源地址:https://blog.csdn.net/uncle_ll/article/details/128481675
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本文标题: Pandas 替换 NaN 值
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