sql语句中日期相减的操作实例代码

select GETDATE(),NOW() FROM t_表名;

select curdate(),NOW() FROM TB_表名;

select (NOW()-日期时间字段) FROM T_表名;

select (curdate()-日期时间字段) FROM T_表名;

select datediff(year, 开始日期,结束日期) FROM T_表名;;

select datediff(quarter, 开始日期,结束日期) FROM T_表名;

select datediff(month, 开始日期,结束日期) from 表名;

select datediff(day, 开始日期,结束日期) FROM T_表名; 

select datediff(week, 开始日期,结束日期) FROM T_表名;

select datediff(hour, 开始日期,结束日期) FROM T_表名;

select datediff(minute, 开始日期,结束日期) FROM T_表名;

select datediff(second, 开始日期,结束日期) FROM T_表名; 

select (CURDATE() - 6) as dateList
uNIOn
select (CURDATE() - 5) as dateList
union
select (CURDATE() - 4) as dateList
union
select (CURDATE() - 3) as dateList
union
select (CURDATE() - 2) as dateList
union
select (CURDATE() - 1) as dateList
union
select (CURDATE() - 0) as dateList

SELECT NOW(), CURDATE(), CURTIME()

declare @t table
(
beginday int,
begintime varchar(20),
endday int,
endtime varchar(20)
)

insert @t select 1,"16:00",2,"12:20"
union all select 1,"3:00",3,"19:10"
select

date=rtrim(date/60)+":"+rtrim(date%60)
from
(select date=datediff(mi,1,dateadd(d,endday-beginday,beginday)-begintime+endtime)from @t )t
date
-------------------------
20:20
64:10

declare @t table(开始天数 varchar(10),开始时间 varchar(10),到达天数 varchar(10),到达时间 varchar(10))
insert @t select "1", "16:00","2","12:20"
--如果开始天数，到达天数大于31
select 到达天数 * 24 + datepart(hh,到达时间) - 开始天数 * 24 - datepart(hh,开始时间)
from @t