关于二分法查找Java的实现及解析

package search;
import java.util.ArrayList;
import java.util.List;
public class BinarySearch {
    public static void main(String[] args) {
        int[] array = {1,1,1,2,3,4,5,6,7};
        List<Integer> integers = binarySearch(array, 0, array.length - 1, 1);
//        for (Integer integer : integers) {
//            System.out.print(integer+ " ");
//        }
        System.out.println(integers);
    }
    public static List<Integer> binarySearch(int[] array, int left, int right, int value){
        //如果左索引大于右索引，则说明全部遍历完了，也没有找到相应的值，返回空集合即可
        if (left>right){
            return new ArrayList<Integer>();
        }
        //获取中间值的下标（二分）
        int mid = (left+right)/2;
        //如果要找的值比中间值小，则继续向左找
        if (value < array[mid]){
            return binarySearch(array, left, mid-1, value);
        //要找的值比中间值小大，则向右找
        }else if (value > array[mid]){
            return binarySearch(array, mid+1, right, value);
        //否则，说明相等，找到了
        }else {
            //找到一个，还需要向左右找找看有没有相同的值
            List<Integer> resultList = new ArrayList();
            //向左循环找，如果有，则加入到集合中
            int temp = mid - 1;
            while (temp>=0 && array[temp] == value){
                resultList.add(temp);
                temp -= 1;
            }
            //向右循环找，如果有，则加入到集合中
            temp = mid + 1;
            while (temp < array.length && array[temp] == value){
                resultList.add(temp);
                temp += 1;
            }
            //将一开始找到的那个索引页加入到集合中。
            resultList.add(mid);
            return resultList;
        }
    }
    
    //以下这段代码来自百度百科，供大家参考。
    public static int binarySearch(Integer[] srcArray, int des) {
        //定义初始最小、最大索引
        int start = 0;
        int end = srcArray.length - 1;
        //确保不会出现重复查找，越界
        while (start <= end) {
            //计算出中间索引值
            int middle = (end + start)>>>1 ;//防止溢出
            if (des == srcArray[middle]) {
                return middle;
                //判断下限
            } else if (des < srcArray[middle]) {
                end = middle - 1;
                //判断上限
            } else {
                start = middle + 1;
            }
        }
        //若没有，则返回-1
        return -1;
    }
}

package search;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class BinarySearch2 {
    public static void main(String[] args) {
        int[] array = {1,1,1,1,1,2,3,4,5,6,7};
        System.out.println(BinarySearch2.binarySearch(array, 7));
    }
    public static List<Integer> binarySearch(int[] array, int key){
        List<Integer> resultList = new ArrayList<>();
        int start = 0;
        int end = array.length - 1;
        while (start <= end){
            int mid = (start + end) / 2;
            int midValue = array[mid];
            if (key > midValue){
                //key比中间值大。向右找
                start = mid + 1;
            } else if (key < midValue){
                //key比中间值小。向左找
                end = mid - 1;
            } else {
                //否则就找到了
                //先向左找有没有相同值
                int temp = mid -1;
                while (temp >= start && array[temp] == key){
                    resultList.add(temp);
                    temp -= 1;
                }
                //将一开始找到的加入结果集
                resultList.add(mid);
                //再向右找找有没有相同值
                temp = mid + 1;
                while (temp <= end && array[temp] == key){
                    resultList.add(temp);
                    temp += 1;
                }
                break;
            }
        }
        return resultList;
    }
}

public class BinarySearch {
    
    //循环
    
    private static int binarySearchByCycle(int[] arr,int num) {
        int start = 0;
        int end = arr.length - 1;
        while (start <= end){
            int mid = (start + end) / 2;
            if(num == arr[mid]){
                return mid;
            }else if(num > arr[mid]){
                start = mid + 1;
            }else {
                end = mid - 1;
            }
        }
        return -1;
    }
    //递归
    
    private static int binarySearchByRecursion(int[] arr,int num,int start,int end) {
        int mid = (start + end) / 2;
        if(num == arr[mid]){
            return mid;
        }else if(num > arr[mid]){
            start = mid + 1;
        }else {
            end = mid - 1;
        }
        if(start <= end){
            mid = binarySearchByRecursion(arr,num,start,end);  //递归继续寻找
        }else {
            mid = -1;
        }
        return mid;
    }
}