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目录使用readLine() 乱码的解决本人在公司开发程序遇到了读取一行乱码小结一下调用readLine的乱码问题下面提供的是readLine字符流指定编码方式的方法使用readLi
eclipse 默认为utf-8
FileInputStream f4 = new FileInputStream(new File("F:\\bb.txt"));
BufferedReader bufferedReader2 = new BufferedReader(new InputStreamReader(f4));
String readLine = bufferedReader2.readLine(); //会输出乱码
测试文件有两个文本文件分别为,aa.txt (UTF-8编码),bb.txt(GB2312编码)两个文件中的内容都为一个字符 中:
前提知识: utf-8中文占三个字节,GB2312中文占两个字节
测试 代码:
public class EncodeTest {
@Test
public void test1() throws Exception{
FileInputStream f1 = new FileInputStream(new File("F:\\aa.txt"));
byte[] b1 = new byte[f1.available()];
f1.read(b1);
for(byte b : b1){
System.out.println(b);
}
System.out.println(new String(b1));
System.out.println("++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++");
FileInputStream f2 = new FileInputStream(new File("F:\\bb.txt"));
byte[] b2 = new byte[f2.available()];
f2.read(b2);
for(byte b : b2){
System.out.println(b);
byte[] tb = new byte[]{b};
String lm = new String(tb);
System.out.println("当前乱码"+lm);
byte[] lm_b = lm.getBytes();
System.out.println("-----------乱码 start--------");
for(byte bn: lm_b){
System.out.println(bn);
}
System.out.println("-----------乱码 end--------");
}
System.out.println(new String(b2,"gb2312"));
System.out.println("++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++");
FileInputStream f3 = new FileInputStream(new File("F:\\bb.txt"));
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(f3));
String readLine2 = bufferedReader.readLine();
byte[] b3 = readLine2.getBytes("UTF-8");
for(byte b : b3){
System.out.println(b);
}
System.out.println(new String(b3));
System.out.println("++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++");
FileInputStream f4 = new FileInputStream(new File("F:\\bb.txt"));
BufferedReader bufferedReader2 = new BufferedReader(new InputStreamReader(f4,"GB2312"));
String readLine = bufferedReader2.readLine();
byte[] b4 =readLine.getBytes("UTF-8");
for(byte b : b4){
System.out.println(b);
}
System.out.println(new String(b4));
System.out.println("++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++");
}
}
通过分析打印结果:
-28 #字节1
-72 #字节2
-83 #字节3
中 #utf-8 解码后字符为:中,没有出现乱码
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
-42 #字节1
当前乱码� #将 -42 按照utf-8 解码后的字符是乱码,然后再将乱码按照utf-8编码得到的字节如下
-----------乱码 start--------
-17
-65
-67
-----------乱码 end--------
-48 #字节2
当前乱码� ##将 -48 按照utf-8 解码后的字符是乱码,然后再将乱码按照utf-8编码得到的字节如下
-----------乱码 start--------
-17
-65
-67
-----------乱码 end--------
中 # 将 字节1: -42和字节2:-48 按照 gb2312 解码 后为字符 中
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
-17 # 这里为readline()方法没有设置使用eclipse默认编码 默认使用utf-8 (读取bb.txt)
-65
-67
-17
-65
-67
�� # 输出的中文为乱码
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
-28 #这里为readline()方法设置了编码为GB2312 读取一行文字为中 (读取bb.txt)
-72
-83
中
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
new BufferedReader(new InputStreamReader(f4)); 默认用utf-8去解码字节,而bb.txt文件内容的字符是gb2312 所以该 中 字符在磁盘中占两个字节,而utf-8编码集中的中文占3个字节,而readline()的时候发现是两个字节,当前使用的又是utf-8,所以java底层就将这两个字节单独使用utf-8进行了解码, 每一个字节 使用utf-8编码一次为 一个char字符,所以经过utf-8将两个字节分别解码后的最终数据为两个乱码字符,
读者可以看上面的代码和打印的信息,两字符个乱码编码后的字节分别为-17 -65 -67(红色),和上面单独将一个字节用utf-8 接码后的字符再按照utf-8编码后得到的字节 -17 -65 -67(蓝色)一样,也就是说 当字节按照utf-8 解码时在utf-8编码集中找不到对应的正确的字符时就会默认作为� 输出,而� 对应的utf-8 字节 -17 -65 -67。所以当找不到对应正确的编码字符时都会按照 -17 -65 -67 对应的 字符 � 输出。
常识: 当使用 new BufferedReader(new InputStreamReader(f4),"文本源的编码") 文本源的编码一定要写。这样就不会有乱码。
readLine是一个很好用的方法,但是作为字符流的方法,确实会遇到各种关于编码方面的问题。但是用字节流来处理数据,比如说一个文本文件,要作按行处理的话,又会显得很不灵活。
//定义一个File对象
File someFile = new File("somefile.txt");
//输入流
FileInputStream fis = new FileInputStream(someFile);
InputStreamReader isr = new InputStreamReader(fis,"UTF-8"); //指定以UTF-8编码读入
BufferedReader br = new BufferedReader(isr);
//输出流
FileOutputStream fos = new FileOutputStream(someFile + ".生成的文件.txt");
OutputStreamWriter osw = new OutputStreamWriter(fos, "UTF-8"); //指定以UTF-8编码输出
while ((line = br.readLine()) != null) {
//osw.write("write something");
osw.write(line);
}
//关闭IO流
br.close();
osw.close();
以上为个人经验,希望能给大家一个参考,也希望大家多多支持编程网。
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本文标题: java 使用readLine() 乱码的解决
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