手把手教你使用Python解决简单的zip文件解压密码

import zipfile
import time
import threading
startTime = time.time()
# 判断线程是否需要终止
flag = True
 
 
def extract(passWord, file):
    try:
        password = str(password)
        file.extractall(path='.', pwd=password.encode('utf-8'))
        print("the password is {}".fORMat(password))
        nowTime = time.time()
        print("spend time is {}".format(nowTime-startTime))
        global flag
        # 成功解压其余线程终止
        flag = False
    except Exception as e:
        print(e)
 
 
def do_main():
    zfile = zipfile.ZipFile("test.zip", 'r')
    # 开始尝试
    for number in range(1, 9999):
        if flag is True:
            t = threading.Thread(target=extract, args=(number, zfile))
            t.start()
            t.join()
 
 
if __name__ == '__main__':
    do_main()

import zipfile
import random
import time
import sys
 
 
class MyIterator():
    # 单位字符集合
    letters = 'abcdefghijklmnopqrstuvwxyz012345678'
    min_digits = 0
    max_digits = 0
 
    def __init__(self, min_digits, max_digits):
        # 实例化对象时给出密码位数范围，一般4到10位
        if min_digits < max_digits:
            self.min_digits = min_digits
            self.max_digits = max_digits
        else:
            self.min_digits = max_digits
            self.max_digits = min_digits
 
    # 迭代器访问定义
    def __iter__(self):
        return self
 
    def __next__(self):
        rst = str()
        for item in range(0, random.randrange(self.min_digits, self.max_digits+1)):
            rst += random.choice(MyIterator.letters)
        return rst
 
 
def extract():
    start_time = time.time()
    zfile = zipfile.ZipFile("test.zip")
    for p in MyIterator(5, 6):
        try:
            zfile.extractall(path=".", pwd=str(p).encode('utf-8'))
            print("the password is {}".format(p))
            now_time = time.time()
            print("spend time is {}".format(now_time-start_time))
            sys.exit(0)
        except Exception as e:
            pass
 
 
if __name__ == '__main__':
    extract()