python中字典和列表的相互嵌套问题详解

p={'name':'lin','age':21}
y={'name':'xue','age':20}
c=[p,y]
print(c)

print(f"person's name is {people[0].get('name')}")
print(f"{people[1].get('name')}'s age is {people[1].get('age')}")
#先用person[0/1]访问列表里的元素(字典),再用get方法访问字典里的值

for person in people:                                            
#将列表中的字典，依次赋值给person                       
    print(f"{person['name']}'s age is {person['age']}")          
    #取出每个循环里变量person（字典）的键和值

for person in people:    
    #在每个遍历的字典里再进行嵌套（内层循环）
    for k,v in person.items():          
        print(f"{k}:{v}")

favourite_places={
    'lin':['beijing','tianjin'],
    'jing':['chengdu','leshan'],
    'huang':['shenzhen']
}
#访问字典中的值可以用：dict_name[key]
print(favourite_places['lin'])
#访问列表里面的元素用索引：list_name[索引]
print(favourite_places['lin'][0].title())

for i in favourite_places['lin']:     
    print(i.title())

for name,place in favourite_places.items():
    print(f"{name.title()}'s favourite places are {place}")

for names,places in favourite_places.items():  #对三个键值对先进行一个大循环
    print(f'{names.title()} favourite places are:') #在大循环里每一组键值对开头先打印这句话
    for place in places:      #之后再对值进行一个小循环，打印出值中的每个元素
        print(place.title())

p={'name':'lin','age':21}
y={'name':'xue','age':20}
c={p,y}
print(c)

users={
    'a':{'name':'lin','age':21},
    'b':{'name':'xue','age':20}
}
print('-----------直接访问输出-------------------')
print(users['a']['name'],users['a']['age'])
print(users['b']['name'],users['b']['age'])
print('\n-----------循环嵌套的方法输出-------------------')
for username,userinfo in users.items():
    print('\n'+username+':')
    for name,age in userinfo.items():
        print(name,age)