springsecurity结合jwt实现用户重复登录处理

@Override
protected void doFilterInternal(httpservletRequest request, HttpServletResponse response, FilterChain filterChain) throws ServletException, IOException {
    String jwt = resolveToken(request);
    //重复登录只校验带有合法jwt的  放过验证码以及免鉴权的那些请求
    if (null == jwt || "null".equalsIgnoreCase(jwt) || !this.tokenProvider.validateToken(jwt)) {
        filterChain.doFilter(request, response);
        return;
    }

    if (isAccessAllowed(jwt)) {
        filterChain.doFilter(request, response);
        return;
    }

    // 账号重复登录，跳转登录页面 loGout
    logout(response);
}


private boolean isAccessAllowed(String token) {
    Authentication authentication = this.tokenProvider.getAuthentication(token);
    String redisToken = redisTemplate.opsForValue().get(Constants.PREFIX_LOGIN_USER+authentication.getName());
    //redisToken为空 说明第一次登陆 放过并加入redis
    if(!StringUtils.hasLength(redisToken)){
        redisTemplate.opsForValue().set(Constants.PREFIX_LOGIN_USER+authentication.getName(),token,
          86400, TimeUnit.SECONDS);
        return true;
    }
    //redis token和当前token一致  说明是当前登陆用户访问  放过
    if(token.equals(redisToken)){
        return true;
    }
    //redis token和当前token不一致，比较两个token的创建时间，如果当前token大于redistoken 就说当前是最新的，放入redis并放过
    //否则就说明redis里已有最新的token，当前token应该过期，不放行
    Date date = this.tokenProvider.getIssueAt(token);
    Date redisDate = this.tokenProvider.getIssueAt(redisToken);
    if(date.after(redisDate)){
        redisTemplate.opsForValue().set(Constants.PREFIX_LOGIN_USER+authentication.getName(),token,
          86400, TimeUnit.SECONDS);
        return true;
    }else{
        return false;
    }

}


private void logout(HttpServletResponse response){
    response.setStatus(HttpStatus.FORBIDDEN.value());
    response.setContentType(MediaType.APPLICATION_JSON_UTF8_VALUE);
    try {
        jsONObject resultObj = new JSONObject();
        resultObj.putOnce("data","账号已在别的地方登录，请重新登录");
        response.getWriter().print(resultObj.toString());
    } catch (IOException e) {
        e.printStackTrace();
    }
}